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What is the problem with the following code segment? while ((fgets(receiving array,50,file_ptr)) != EOF)
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71) #include<stdio.h> main() { const int i=4; float j; j = ++i; printf("%d %f", i,++j); }
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if i have 10 steps in a job.i run all steps and execute only 3rd step how it is possible? |
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95) func(a,b) int a,b; { return( a= (a==b) ); } main() { int process(),func(); printf("The value of process is %d !
",process(func,3,6)); } process(pf,val1,val2) int (*pf) (); int val1,val2; { return((*pf) (val1,val2)); }
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