INTERVIEW QUESTIONS C ARRAYS IN C DETAILS

Question: Can the sizeof operator be used to tell the size of an array passed to a function?

Answer: No. There’s no way to tell, at runtime, how many elements are in an array parameter just by looking at the
array parameter itself. Remember, passing an array to a function is exactly the same as passing a pointer to
the first element.

No. There’s no way to tell, at runtime, how many elements are in an array parameter just by looking at the
array parameter itself. Remember, passing an array to a function is exactly the same as passing a pointer to
the first element. Source: CoolInterview.com

In VC++, this is wat i tried

main()
{
int a[10];
printf("%d", sizeof(a);
}

Output: 40

This shows dat the sizeof can be operated on arrays as well. Source: CoolInterview.com

20 Source: CoolInterview.com

yes Source: CoolInterview.com

yes Source: CoolInterview.com

GOD!!!! so many 'yes'...

The answer is NO.. Pass the array element to a function and see. The array is passed as a pointer (pointer to the begining address of the array).. Source: CoolInterview.com

no,size of operator is compile time operator, it is used for determine the lenght of array and structure but in compile time not run time Source: CoolInterview.com

sizeof() is an operator, it is not a function, this is reason you are getting the answer out at 40.

Try the following:

# include <stdio.h>
# include <malloc.h>

void printf_sz(int a[])
{
printf("
Sizeof : %d", sizeof(a));
}



main()
{
int a[20];

printf ("
Sizeof : %d", sizeof(a));

printf_sz(a);


}

The output of the above program is 80 and 4.

Check for yourself
Source: CoolInterview.com

Yes, there is a way -

#include<conio.h>
#include<stdio.h>

int main()
{
int arr[] = {4, 2, 4, 5, 2, 3, 1};
int arr_size = sizeof(arr)/sizeof(arr[0]);
printf("Array size = %d", arr_size);
getchar();
return 0;
} Source: CoolInterview.com

hey we can not calculate size of the array element we can only calculate the size of the datatype only try this
headerfile
void main()
{
clrscr();
int i;
printf("the size of i is ",size of (i));
getch();
} Source: CoolInterview.com

No,It is not possible ..

#include<stdio.h>
#include<conio.h>

void sourav(int a[])
{

int p=sizeof(a);
printf("%d",p);

}


int main()
{

int a[10];
sourav(a);

getch();
return 0;
}

This program gives output 4.But it is not correct ,so it is not possible. Source: CoolInterview.com

how about useing the strlen() instead of size of it'll do more favout Source: CoolInterview.com

we can know about the no. of elements in an array by the help of "sizeof()" operator if and only if we know the data type and the total bytes hold by that array... Source: CoolInterview.com

yo shd do practicaly n clear here yo r not goin to get any thng Source: CoolInterview.com

#include<stdio.h>
#include<conio.h>

void main()
{

long int a[10];
clrscr();
printf("%d", sizeof(a));
getch();
}
output: 20,in case of char output is 10
hey we can calculate size of the array element.which depends on the datatype only try this Source: CoolInterview.com

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