INTERVIEW QUESTIONS GENERAL QUANTITATIVE DETAILS

Question: If Log2 x - 5 Log x + 6 = 0, then what would the value / values of x be?

Answer: x = e2 or e3

x = e2 or e3 Source: CoolInterview.com

x = e2 or e3 Source: CoolInterview.com

(2/e^-6)^(1/4) Source: CoolInterview.com

x=100 or x=1000
since base of log is not mentioned so it is taken base 10 Source: CoolInterview.com

x=100 or x=1000
since base of log is not mentioned so it is taken base 10 Source: CoolInterview.com

log2x-5logx+6=0
log2+logx-logx-4logx+6=0
log2-4logx +6=0
log2-4logx+log10^6=0
log2+log10^6=logx^4
logx^4=log(2*(10^6))
remove log
x^4=2*(10^6)
therefore
x=root of (root of(2*10^6))
x=21.147

Source: CoolInterview.com

x=e^-1.2 Source: CoolInterview.com

log2x-5logx+6 = 0
log2+logx-5logx+6 = 0
log2+6 = 4logx
e^(log2+6) = e^[log(x^4)]
2(e^6) = x^4

let r = |[2(e^6)]^(1/4)|
and i^2 = -1

then the solutions of x are +r, -r, +r*i and -r*i. Source: CoolInterview.com

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