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Question: There is a string 120000 12 0 .125 , how you will find the position of the decimal place?

Answer: INSTR('120000 12 0 .125',1,'.')
output 13

INSTR('120000 12 0 .125',1,'.')
output 13 Source: CoolInterview.com

INSTR('120000 12 0 .125',1,'.')
output 13

the answer is
INSTR('120000 12 0 .125','.')
output 13

if you will use
INSTR('120000 12 0 .125',1,'.')
it will give u error as (invalid number)
so please use it as below
INSTR('120000 12 0 .125','.')
output 13

Thanks
Mujahid khan

Source: CoolInterview.com

CHARINDEX('.','120000 12 0 .125')
Output: 13 Source: CoolInterview.com

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