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Question: Given a Class B Network with subnet mask of 255.255.248.0 and a packet addressed to 130.40.32.16, what is the subnet address?
Answer: Take the 2 addresses, write them in binary form, then AND them. The answer is 130.40.32.0
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Question:
Given a Class B Network with subnet mask of 255.255.248.0 and a packet addressed to 130.40.32.16, what is the subnet address?
Answer:
Take the 2 addresses, write them in binary form, then AND them. The answer is 130.40.32.0 Source: CoolInterview.com
The answer should be 130.40.32.0
The subnet address in the IP address with the network address and without host bits. To find it we do an AND operation between the IP address and the subnet mask.
Converting 130.40.32.16 to binary:
10000010.00101000.00100000.00010000
Converting the subnet mask 255.255.248.0 to binary:
11111111.11111111.11111000.00000000
ANDing the two binaries we get:
10000010.00101000.00100000.00000000
Back to decimal we get: 130.40.32.0 Source: CoolInterview.com
Answered by: Alok Kr. Singh | Date: 1/21/2010
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Given a Class B Network with subnet mask of 255.255.248.0 and a packet addressed to 130.40.32.16, what is the subnet address? Answers:
Take the 2 addresses, write them in binary form, then AND them. The answer is 130.40.32.0
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The answer should be 130.40.32.0
The subnet address in the IP address with the network address and without host bits. To find it we do an AND operation between the IP address and the subnet mask.
Converting 130.40.32.16 to binary:
10000010.00101000.00100000.00010000
Converting the subnet mask 255.255.248.0 to binary:
11111111.11111111.11111000.00000000
ANDing the two binaries we get:
10000010.00101000.00100000.00000000
Back to decimal we get: 130.40.32.0
Source: CoolInterview.com
Answered by: Bismillah Ahmed | Date: 7/13/2010
| Contact Bismillah Ahmed
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