90) main(){ unsigned int i; for(i=1;i>-2;i--) printf("c aptitude"); } - Explanation: i is an unsigned integer. It is compared with a signed value. Since the both types doesn't match, signed is promoted to unsigned value. The unsigned equivalent of -2 is a huge value so condition becomes false and control comes out of the loop.

CoolInterview.com - World's Largest Collection of Interview Questions & Answers, FAQs, queries, sample papers, exam papers, dumps, what, why, how, where, when questions

OneStopTesting.com - Testing EBooks, Tutorials, Articles, Jobs, Training Institutes etc.
OneStopGate.com - Gate EBooks, Tutorials, Articles, FAQs, Jobs, Training Institutes etc.
OneStopMBA.com - MBA EBooks, Tutorials, Articles, FAQs, Jobs, Training Institutes etc.
OneStopIAS.com - IAS EBooks, Tutorials, Articles, FAQs, Jobs, Training Institutes etc.
OneStopSAP.com - SAP EBooks, Tutorials, Articles, FAQs, Jobs, Training Institutes etc.
OneStopGRE.com - of GRE EBooks, Tutorials, Articles, FAQs, Jobs, Training Institutes etc.

Sponsored Links

Interview Questions

INTERVIEW QUESTIONS

MAINFRAME

JCL

DETAILS

Question: 90) main(){
unsigned int i;
for(i=1;i>-2;i--)
printf("c aptitude");
}

Answer: Explanation:
i is an unsigned integer. It is compared with a signed value. Since the both types doesn't match, signed is promoted to unsigned value. The unsigned equivalent of -2 is a huge value so condition becomes false and control comes out of the loop.

Category	JCL Interview Questions & Answers - Exam Mode / Learning Mode
Rating	(0.3) By 8205 users
Added on	9/3/2014
Views	66444
Rate it!

Question: 90) main(){
unsigned int i;
for(i=1;i>-2;i--)
printf("c aptitude");
}

Answer:

Explanation:
i is an unsigned integer. It is compared with a signed value. Since the both types doesn't match, signed is promoted to unsigned value. The unsigned equivalent of -2 is a huge value so condition becomes false and control comes out of the loop.
Source: CoolInterview.com

If you have the better answer, then send it to us. We will display your answer after the approval.

Rules to Post Answers in CoolInterview.com:-

There should not be any Spelling Mistakes.

There should not be any Gramatical Errors.

Answers must not contain any bad words.

Answers should not be the repeat of same answer, already approved.

Answer should be complete in itself.

	Related Questions	View Answer
	89) main(){ int a= 0;int b = 20;char x =1;char y =10; if(a,b,x,y) printf("hello"); }	View Answer
	88) int i; main(){ int t; for ( t=4;scanf("%d",&i)-t;printf("%d ",i)) printf("%d--",t--); } // If the inputs are 0,1,2,3 find the o/p	- JCL Interview Questions & Answers"> View Answer
	87) main() { int i; i = abc();Answer: 0..0 Explanation: The value of i is 0. Since this information is enough to determine the truth value of the boolean expression. So the statement following the if statement is not executed. The values of i and j remain unchanged and get printed. printf("%d",i); } abc() { _AX = 1000; }	View Answer
	85) #include<stdio.h> main() { FILE *ptr; char i; ptr=fopen("zzz.c","r"); while((i=fgetch(ptr))!=EOF) printf("%c",i); }	wh - JCL Interview Questions & Answers"> View Answer
	83) # include<stdio.h> aaa() { printf("hi"); } bbb(){ printf("hello"); } ccc(){ printf("bye"); } main() { int (*ptr[3])(); ptr[0]=aaa; ptr[1]=bbb; ptr[2]=ccc; ptr[2](); }	} bbb(){ printf("hello"); - JCL Interview Questions & Answers"> View Answer
	82) # include <stdio.h> int one_d[]={1,2,3}; main() { int ptr; ptr=one_d; ptr+=3; printf("%d",ptr); }	View Answer
	81) main(int argc, char **argv) { printf("enter the character"); getchar(); sum(argv[1],argv[2]); } sum(num1,num2) int num1,num2; { return num1+num2; }	getchar(); sum(argv[ - JCL Interview Questions & Answers"> View Answer
	81) main(int argc, char **argv) { printf("enter the character"); getchar(); sum(argv[1],argv[2]); } sum(num1,num2) int num1,num2; { return num1+num2; }	getchar(); sum(argv[ - JCL Interview Questions & Answers"> View Answer
	80) main() { char c=' ',x,convert(z); getc(c); if((c>='a') && (c<='z')) x=convert(c); printf("%c",x); } convert(z) { return z-32; }	View Answer
	79) main() { char p; int q; long *r; p=q=r=0; p++; q++; r++; printf("%p...%p...%p",p,q,r); }	View Answer
	79) main() { char p; int q; long *r; p=q=r=0; p++; q++; r++; printf("%p...%p...%p",p,q,r); }	View Answer
	78) main() { int i=_l_abc(10); printf("%d ",--i); } int _l_abc(int i) { return(i++); }	} int _l_abc(int i) { re - JCL Interview Questions & Answers"> View Answer
	77) struct point { int x; int y;};struct point origin,pp; main() { pp=&origin; printf("origin is(%d%d) ",(pp).x,(*pp).y); printf("origin is (%d%d) ",pp->x,pp->y); }	View Answer
	76) struct aaa{ struct aaa prev; int i; struct aaa next; }; main() { struct aaa abc,def,ghi,jkl; int x=100; abc.i=0;abc.prev=&jkl; abc.next=&def; def.i=1;def.prev=&abc;def.next=&ghi; ghi.i=2;ghi.prev=&def; ghi.next=&jkl; jkl.i=3;jkl.prev=&ghi;jkl.next=&abc; x=abc.next->next->prev->next->i; printf("%d",x); }	View Answer
	74) main() { int i=5,j=6,z; printf("%d",i+++j); }	} - JCL Interview Questions & Answers"> View Answer
	73) #include<stdio.h> main() { register i=5; char j[]= "hello"; printf("%s %d",j,i); }	View Answer
	72) #include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int p,q; p=&a[2][2][2]; q=*a; printf("%d..%d",p,*q); }	View Answer
	71) #include<stdio.h> main() { const int i=4; float j; j = ++i; printf("%d %f", i,++j); }	View Answer
	70) main() { int i=-1; -i; printf("i = %d, -i = %d ",i,-i); }	} - JCL Interview Questions & Answers"> View Answer
	69) main() { int j; { int i=10; j=&i; } printf("%d",j); }	View Answer

Please Note: We keep on updating better answers to this site. In case you are looking for Jobs, Pls Click Here Vyoms.com - Best Freshers & Experienced Jobs Website.

View All JCL Interview Questions & Answers - Exam Mode / Learning Mode