39) main() { int i=0; for(;i++;printf("%d",i)) ; printf("%d",i); } - Answer: 1 Explanation: before entering into the for loop the checking condition is "evaluated". Here it evaluates to 0 (false) and comes out of the loop, and i is incremented (note the semicolon after the for loop).

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Question: 39) main()
{
int i=0;

for(;i++;printf("%d",i)) ;
printf("%d",i);
}

Answer: Answer:
1
Explanation:
before entering into the for loop the checking condition is "evaluated". Here it evaluates to 0 (false) and comes out of the loop, and i is incremented (note the semicolon after the for loop).

Category	JCL Interview Questions & Answers - Exam Mode / Learning Mode
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Added on	9/2/2014
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Question: 39) main()
{
int i=0;

for(;i++;printf("%d",i)) ;
printf("%d",i);
}

Answer:

Answer:
1
Explanation:
before entering into the for loop the checking condition is "evaluated". Here it evaluates to 0 (false) and comes out of the loop, and i is incremented (note the semicolon after the for loop).

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