INTERVIEW QUESTIONS PROGRAMMING LANGUAGES C DETAILS

Question: Why does a linker error occurs for the segment:
main()
{
extern int i;
i=20;
printf("%d",sizeof(i));
}

Answer: You cannot define the value of an extern variable, should be defined in some other header or cpp file, so it will give a linker error.

You cannot define the value of an extern variable, should be defined in some other header or cpp file, so it will give a linker error. Source: CoolInterview.com

Here variable 'i' has decalred as extern. Then, compiler won't allow any memory to this variable and later, we are trying to access a variable for which memory was not allocated at all. Hence, it gives linker error. Source: CoolInterview.com

The extern specifies only declaration ie it indicates to the compiler that "i" will be used(in the scope of its declaration) but its memory is allocated in some other file. Now since memory is not allocated to i,its size is unknown and we cannot use it.The error is detected by linker since linker does the task of external references. Source: CoolInterview.com

ans is 2, because the purpose of sizeof() is sizeof operator to calculate the number of elements in the array. Source: CoolInterview.com

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