INTERVIEW QUESTIONS J2EE JAVA DETAILS

Question: Solve it...
public class test {

public static void main(String[] args)
{
int i=5;
i=i++;
System.out.println("result::"+i);
}
}

Answer: i=i++

can be taken up as i=(i=i+1)

here the value of i=5 initially .. then which one is it.. i=5 or i++ in the next line ..?

i=i++

can be taken up as i=(i=i+1)

here the value of i=5 initially .. then which one is it.. i=5 or i++ in the next line ..?
Source: CoolInterview.com

i m not satisfied with above answer i think it shud be like or we can take this :

public class Test {
public static void main(String p[]) {

for(int i=5; i<20; i++)
System.out.println("result" + i);
}
}
plz tell me if i am wrong
Source: CoolInterview.com

int i=5;
first it stores value 5.
i=i++;
when this statement is executed first it copies value 5 in i.again it increments value assigning value to the same variable i.so it will becomes 6.
if we r doing like this
int i=5;
int a;
a=i++;
System.out.println(a);
it prints 5;
System.out.println(i);
it prints 6; Source: CoolInterview.com

here the increment is the post increment so the value of the i is 5 Source: CoolInterview.com

In my point of view the answer is 5 because whenever you increment a value with ++ operator it doesnot get display in the next line we have to declare one more variable for it and then show it there in this program the answer is 5 we can pront the i++ value as
public class test {

public static void main(String[] args)
{
int i=5;
i=i+1;
System.out.println("result::"+i);
}
}
In the above program it will print six which shows the difference that in the ++ operator and +1
Source: CoolInterview.com

answer is 5.
the answer is 6 if i=++i. Source: CoolInterview.com

The answer is 5.

To see what the answer is the best way is to type this snippet into a file,compile it and run it.
You'll get the answer 5.

It is how post-increment works.

Use the current value of i(that is to assign itself to i) then increment it. Source: CoolInterview.com

The answer will be 6 because i++ increase the value of i by 1 so i will store the value 5+1 i.e. 6.
Source: CoolInterview.com

The answer is 6. I will give u the valid reason. Because i++ is a Right to Left associatve, the evaluation starts from right. So, the increment of i variable takes place first and then assigned to i. Source: CoolInterview.com

The answer is 5.

int i=5;//initial value of i is 5
i=i++;//No change, if ++i then 5 get incremented.
Source: CoolInterview.com

The answer is 5.
int i=5;
i=i++;
here i value is 5 so first time it will assign then increment.
Source: CoolInterview.com

here answer is 5
first thing is that initially its value was i=5
after post increment if it was asked to print value of i then it would be i=5;
because first value will print and then new value will store in i.
Source: CoolInterview.com

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