The answer is 3

The value which is last in the bracket is assigned to a(the variable).If it would have been any other value except 3,then it would have been assigned to 'a'.

Ans : 3

This is because of the comma(,) operator. Whenever any value is assigned using the comma operator, then the last value is assigned to the variable.

Here a = (1,2,3);
it is similar to
a=1;
a=2;
a=3;

if i print value of a after all the three statements, then it will print 3.

Let me take another example:

void main()
{
int a=(2,3,4);
int b= (a,10);
int c = a+b;
printf("Value of c = %d",c);
getch();
}

Here a will contain the value 4 and b will contain the value 10. Hence the value of c will be 14.

Ans : 3

This is because of the comma(,) operator. Whenever any value is assigned using the comma operator, then the last value is assigned to the variable.

Here a = (1,2,3);
it is similar to
a=1;
a=2;
a=3;

if i print value of a after all the three statements, then it will print 3.

Let me take another example:

void main()
{
int a=(2,3,4);
int b= (a,10);
int c = a+b;
printf("Value of c = %d",c);
getch();
}

Here a will contain the value 4 and b will contain the value 10. Hence the value of c will be 14.

3
First a is assigned to 1 then it is replaced by 2 and then 3.
which gives the final output to be 3.

Ans is : 3
if it is int a = (1,2,3,4);
the answer will be 4.

The OutPut Will be 3
because the precedence of braces() is right to left
so 3 will be assigned to int a.

output will be 3 because compiler
read from right firstly he read 3
and assign a=3 and then print.

Compile time error will be generated as the integer a is not correctly initialized.

syntax error, a is not an array.

The answer will be: 3
Reason: The comma operator has associativity from left to right like assignment operator. So the right most value i.e. 3 will be assigned to a.

output is 3 becuse 3 is assigned to a and it get printed.

3

answer will be
3
value of a will updated two times and last value which is 3 will display

3
whatever the integer values assigned as in the program given, the final integer will be the answer for example if it is as below
i-(2,3,4)
answer will be 4.

It will take the last value that is 3 since it is the latest value assigned to it.

3
whatever the last one in bracket is the output.because the last answer is overwritten on the previous ans.

First right hand side of the = is solved i.e (1,2,3)
It has 3 expression separated by coma, like (exp1,exp2,exp3)
it is evaluated from left to right
so exp1 next exp2 finally exp3 is evaluated so the final evaluated result will be assigned to a
so the answer is 3

Output is 3,
because in first a became 1 then it changes to 2 ofter that it changes 3,
Now a value is 3 then we print a value , so the output is 3.
a->1,a=(1)

a->2;a=(1,2)

a->3, a=(1,2,3)
so now a vaule is 3...

This will give u compilation error..That
Declaration is not allowed here....

int a = (1,2,3);

translates into
a = 1;
a = 2;
a = 3;

So, it will print 3.

The answer will be 3. because in c language the assignment of values for the variables will be done from right to left.so right most 3 will be assigned to the variable 'a'

Output is 3,Because the first(1)
value is override by second(2) and second(2) value overide by third(3).

output:
3
reason:we are giving only oone variable for group pf values

3

65
because the variable assigned is not assigned properly so its return the garbage values.

When we are using the printf statement the right most value will be accessed by the variable.That's why 3 is printed.

output: 3
Since printf statement will take up the last value specified in the list of arguments separated by comma.

Answer is 3 because in initialization final value is taken.

3
Because the last assigned value will be taken into account other values(1,2) has no effect.

Ans is a = 3
because as a is single variable so it can hold only one value.First 1 is assigned to a then 1 is overwritten by 2 and then by three so current value is 3 .

ANS : 3.
Reason :U are giving three i/ps.
When executing the result it will print 3 because FIFO

3
Because first the value of a will be 1 after that it will overwrite by 2 and finally value of a will be 3.

The answer is 3.

Because,since the ',' operation value is the right operand,3 will be assigned to a.

Output is 3.

'a' is assigned to the last number when braces are used otherwise '1' would have been the o/p.

i.e, a=1,2,3;
printf("%d",a);

would print '1'.

Here a=3

Reason being that comma has lower precedence, so it will take into account the latest value of variable a.

printf the address of 1
becoz by default array name holds the base address or the address of first element of array.

printf the address of 1
becoz by default array name holds the base address or the address of first element of array.

Answer is 3 because we had using the comma operator. It take last value of intialized variable. Hence 3 was assined to variable of 'a'. So, output will be 3.

I hope useful to u

ANS: 3

because only last assignment it will take . we have assigned 3 as last ,so ans is 3.

Answer 3.
In this case, during the initialisation of variable "a", values 1, 2 and 3 are assigned to "a" in the order 1->2->3.

So finally 3 will be stored in a.

Answer will 3.Because first it is taking 1 after that 2 and then 3.This is equal to this:
a=1;
a=2;
a=3;

output is 3.it take last value of intilized variable.hance 3 was assigned to "a".

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