by using bitwise operators it is possible, for example a=8,ie in binary(00001000) & b=4 in binary (00000100)if we add a,b then we get 12 in binary(00001100)..if u add the binary a,b & convert the answer in to decimal we get 12.. in the c code is:
void main()
{
int a=8,b=4,c;
clrscr();
c=a^b;
printf("%d",c);
getch();
}
so,by using ^ operator we can do that in c.

main()
{
int i,j,k;
printf("Enter the value of i and j");
scanf("%d%d",&i,&j);
if(i<j)
{
for(k=0;k<i;k++)
j++;
}
else
{
for(k=0;k<j;k++)
i++;
}
printf("The required sum is : ",i)
}

#include<stdio.h>
unsigned int add(unsigned int a, unsigned int b)
{
unsigned int c=0;
unsigned int r=0;
unsinged int t=~0;
for (t=~0;t;t>>=1)
{
r<<=1;
r|=(a|b)&c|a&b)&1;
a>>=11;
b>>=1;
}
for(t=~0,c=~t;t;t>>=1)
{
c<<=1;
c|=r&1;
r>>1;
}
int main(int argc,char*argv[])
{
printf("%d+%d=%d
",atoi(argv[1]),atoi(argv[2]),add(atoi(argv[1]),atoi(argv[2])));
return(0);
}

int add(int a, int b)
{
int sum, carry;
sum = a ^ b;
carry = a & b;
while (carry != 0)
{
carry <<= 1;
a = sum;
b = carry;
sum = a ^ b;
carry = a & b;
}
return sum;
}

You should perform OR operation between these numbers.

int main()
{
int i,a, b, sum=0,temp1,temp2,temp3;
int cin=0;

printf("enter input a an b");
scanf("%d
%d",&a,&b);
for(i=0;i<32;i++)
{
temp1=(a>>i)&(1);
temp2=(b>>i)&(1);

temp3 =cin^temp1^temp2;
sum=sum|temp3<<i;
if((temp1&&temp2)||(temp1&&cin)||(cin&&temp2)) cin=1;
else cin=0;
}
printf("%d",sum);
return 0;
}

#include<stdio.h>
void main()
{
int num1 = 10; //First Number
int num2 = 5; //Second Number
int i; // loop counter
int s=0;
for (i=0;i<5;i++)
{
i++;
s++;
}
printf("Sum = %d",s);
}

#include <stdio.h>
int add(int a, int b){
char carry=0;
int result=0,bitshift=0;
while ((a!=0)||(b!=0)){
result=(((a&0x1)^(b&0x1)^carry)<<bitshift)|result;
if (((a&0x1)&(b&0x1))||((a&0x1)&carry)||((b&0x1)&carry)) carry=1;else carry=0;
a=a>>1;b=b>>1;bitshift++;
}
result=(carry<<bitshift)|result;
return result;
}
int main(int argc, char **argv)
{int a=255,b=12;
printf("Total of %d and %d is: %d",a,b,add(a,b));getchar();
return 0;
}

int main()
{
int i,a, b, sum=0,temp1,temp2,temp3;
int cin=0;

printf("enter input a an b");
scanf("%d
%d",&a,&b);
for(i=0;i<32;i++)
{
temp1=(a>>i)&(1);
temp2=(b>>i)&(1);

temp3 =cin^temp1^temp2;
sum=sum|temp3<<i;
if((temp1&&temp2)||(temp1&&cin)||(cin&&temp2)) cin=1;
else cin=0;
}
printf("%d",sum);
return 0;
}

sum of variables a, b
sum = a XOR b;

two variables a,b

sum = (a^b)|((a&b)<<1);

void main()
{
int n1,n2,i;
clrscr();
printf("enter the two no");
scanf("%d %d",&n1,&n2);
for(i=1;i<=n2;i++)
n2=n2+1;
printf("%d",n2);
}

by using vadd() function

#include<stdio.h>
main()
{
int i,j,k;
printf("Enter the value of i and j");
scanf("%d%d",&i,&j);
if(i>j)
{
for(k=0;k<i;k++)
{j++;
}
printf("The required sum is : %d",j);
}
else
{
for(k=0;k<j;k++)
{
i++;
}
printf("The required sum is : %d",i);
}
}

By using Bitwise Operators, we can add 2 nos. But the usage of " ^ " bitwise will not give the correct answer for all values.

#include<stdio.h>
main()
{
int a,b,i;
clrscr();
printf("enter the value of a and b");
scanf("%d %d",&a,&b);
int d=a;
for(i=1;i<=b;i++)
{
a++;
}
if(b==0)
printf("%d",d);
else
printf("%d",a);
}

void main()
{
int n1,n2,i;
scanf("%d %d",&n1,&n2);
for(i=0;i<n2;i++,n1++);
printf("%d",n1);
}

main()
{
int a,b,c;
printf("enter any 2 numbers ");
scanf("%d%d",&a,&b);
while(b)
{
c= (a^b);
b= (a&b)<<1;
a=c;
}
printf("Sum of a and b is %d",c);
}

#include<stdio.h>
main()
{
int a,b;
clrscr();
scanf("%d %d",&a,&b);
a=a+b;
printf("a=%d,b=%d",a=a-b,b=a-b);
}

main()
{
int a = 2, b = 3;
printf("%d",((a ^ b) | (a & b) << 1));
}

main()
{
int a,b,c;
scanf("%d%d",&a,&b);
for(i=1;i<=b;i++)
c=++a;
printf("Sum = %d",c);
}

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