int a=10,b=5;

a=a+b; // a=15
b=a-b; // b=10
a=a-b; // a=5

main()
{
int a,b;
printf("enter the values of a,b");
scanf("%d%d",&a,&b);
a=a+b;
b=a-b;
a=a-b;
printf("after swapping the values of a and b");
}

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;

printf("enter a , b");
scanf("%d%d",&a,&b);
printf("a: %d
b: %d ",a,b);
a=a+b;
b=a-b;
a=a-b;
printf("a: %d",a);
printf("b: %d",b);
getch();
}

main()
{
int a,b;
printf("Enter values for a & b");
scanf("%d""%d",@a,@b);
if(a==b)
printf("enter valid numbers");
else
{
a=a+b; a=a*b;
b=a-b; /*(or)*/ b=a/b;
a=a-b; a=a/b;
}
printf("a=%d b=%d",&a,&b);
}

By using this simple arithmatic you can solve this problem.
======
a=10;
b=20;

a=a+b
b=a-b
a=a-b
======

int a=10, b=20;
a=a+b;
b=a-b;
a=a-b;

code is :
b=a+b;
a=b-a;
b=b-a;

a,b
a=a+b
b=a-b
a=a-b
now a and b are swapped

int i=9,j=8;
i=i+j;
j=i-j;
i=i-j;
printf("J = ",&j);
System.out.println("I =",&i);

int a = 10;
int b = 20;

b = a + b;
a = b - a;
b = b - a;
printf ("a = %d, b = %d
", a, b);

a=a+b;
b=a-b;
a=a-b;

void main()
{int a=50,b=100;
a=a+b; //a=50+100, a= 150
b=a-b; //b=150-100, b= 50
a=a-b; //a=150-50, a=100
}

swapping of two numbers without using temp veriable

int a,b;
a=a+b;
b=a-b;
a=a-b;
now print a and b with swapped values

#include <stdio.h>
void main()
{
int a,b;
printf("
Enter the two number ::");
scanf("%d %d",&a,&b);
/*Swapping*/
a=a+b;
b=a-b;
a=a-b;
printf("The swapped numbers are::%d %d",a,b);
}

one method :

a=a+b;
b=a-b;
a=a-b;


other method :
a^=b^=a;

a=a-b;
b=a+b;
a=b-a;

#include<stdio.h>

int main()
{
int a,b;
printf("
Enter the values for a and b");
scanf("%d%d",&a,&b);
printf("
Value of a and b before swapping are ::
a = %d b = %d

",a,b);
a=a+b;
b=a-b;
a=a-b;
printf("
Value of a and b after swapping are ::
a = %d b = %d

",a,b);
system("pause");
return 0;
}

#include<stdio.h>

int main()
{
int a,b;
printf("Enter the two number a and b
");
scanf("%d%d", &a,&b);
printf("Number before swapping a = %d b = %d", a,b);
a = a + b;
b = a - b;
a = a - b;
printf(" Number after swapping a = %d b = %d", a,b);

#include<stdio.h>

int main()
{
int a,b;
printf("Enter the two number a and b
");
scanf("%d%d", &a,&b);
printf("Number before swapping a = %d b = %d", a,b);
a = a + b;
b = a - b;
a = a - b;
printf(" Number after swapping a = %d b = %d", a,b);
return 0;
}

1st method :
a = a + b;
b = a - b;
a = a - b;

2nd method :
a = a xor b;
b = b xor a;
a = a xor b;

a,b are two variables...
a=a+b;
b=a-b;
a=a-b;

main()
{
int a,b;
printf("Enter values of a,b");
scanf("%d%d",&a,&b);//forex:u enter 100,50
a=a+b;//a=150
b=a-b;//b=100
a=a-b;//a=50
printf("a=%d b=%d",a,b);
}

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int a,b;
printf(" Enter two values");
scanf("%d%d",&a,&b);
a=a-b;
b=abs(a+b);
a=abs(a-b);
printf(" Swaped values are %d,%d",a,b);
getch();
}

#include<stdio.h>
void main()
{
int a=5,b=7;
a=a+b;
b=a-b;
a=a-b;
printf("%d %d",a,b);
}
output:
7 5

a=a+b;
b=a-b;
a=a-b;

If a and b are two variables then swapping can be done in a single statement without using any temporary variable.

a^=b^=a^=b;

main()
{
int x,y;
temp z;
x = y;
y = z;
z = x;
printf("%d%d",x,y);
}

void main()
{
int x=5, y=10;
swap (x,y);
printf(?%d %d
?,x,y);
swap2(x,y);
printf(?%d %d
?,x,y);
}

#define swap(a,b) a=a+b;b=a-b;a=a-b;

void main()
{
int x=5, y=10;
swap (x,y);
printf(?%d %d
?,x,y);
swap2(x,y);
printf(?%d %d
?,x,y);
}

int swap2(int a, int b)
{
int temp;
temp=a;
b=a;
a=temp;
return 0;

}

use, 2 variables a, b.then try this code,

a=a+b;
b=a-b;
a=a-b;

that's it

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
clrscr();
printf("
Enter 2 no: ");
scanf("%d%d",&a,&b);
printf("
Before swapping a=%d b=%d",a,b);
a=(a+b)-(b=a);
printf("
After swapping a=%d b=%d",a,b);
getch();
}

/*this program is executed in
turboc3 */

Using XOR operation will also
Solve the purpose
a=7,
b=10,

a = a^b;//a=13
b = a^b;//b=7
a = a^b;//a=10

a and b are swapped

int a,b;
a=a^b;
b=a^b;
a=a^b;

#include<stdio.h>
#include<conio.h>

main()
{
int a=5,b=7;

a=a^b;
b=a^b;
a=a^b;
printf("a is %d b is %d
",a,b);
getch();
return 0;
}

void main()
{
int a=5,a=10;
printf("
A=%d B=%d",a,b);
a=a-(b=(a=a+b)-b);
printf("
A=%d B=%d",a,b);
}

This snippet of code will swap 2 numbers
a = a + b - (b = a) ;
also we can use ^ operator
a^b;b^a;a^b;

If a and b are two variables then we can swapped with this code
a=a*b/(b=a)

/*using pointers*/
main()
{
int *a=10, *b=4;
printf("BEFORE SWAPPING THE VALUES OF A & B ARE %d%d"*a,*b);
*a=*a+*b; //*a=14
*b=*a-*b; //*b=10;
*a=*a-*b; //*a=4
printf("AFTER SWAPPING THE VALUES OF A & BARE %d%d"*a,*b);
}

#include<stdio.h>
#include<conio.h>
void main()
{
int a=3,b=2;
clrscr();
printf("The values of a and b before swapping are %d%d",a,b);
a^=b^=a^=b;
printf("The values of a and b after swapping are %d%d",a,b);
getch();
}

main()
{
int a=5,b=10;
printf("before swap %d %d",a,b);
a=(a*b)/(b=a);
printf("after swap %d %d",a,b);

#include<stdio.h>
void main()
{
int a,b;
printf("%d%d",a,b);
a=a^b;
b=a^b;
a=a^b;
printf("a=%d,b=%d",a,b);
}

a=10;
b=20
b=((a+b)-(a=b))//in a single line

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
clrscr();
printf("Enter a and b");
scanf("%d%d",&a,&b);
a=a*b;
b= a/b;
a = a/b;
printf("Swapped values are:%d,%d",a,b);
getch();
}

#include<stdio.h>
main()
{
int a,b,i;
clrscr();
printf("enter the value of a and b");
scanf("%d %d",&a,&b);
a=a+b;
printf("a=%d,b=%d",a=a-b,b=a-b);
}

main()
{
int a=6,b=3;
a=a^b;
b=a^b;
a=a^b;
printf("%d %d",a,b);
}
output:
3 6
othermethod
a=a+b;
b=a-b;
a=a-b;

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